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JEE MAIN_2023
S2_25.01.23
Question
The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by
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Select the correct option:
A
$\frac{t_c}{150}=\frac{t_p-180}{100}$
B
$\frac{t_c}{100}=\frac{t_p-30}{150}$
C
$\frac{t_P}{180}=\frac{t_Q-40}{100}$
D
$\frac{t_p}{100}=\frac{t_Q-180}{150}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Hard
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