The instantaneous velocity| RECTILINEAR MOTION| JEEMAIN 2021

JEE MAIN 2021

25-07-21 S2

Question

The instantaneous velocity of a particle moving in a straight line is given as $\mathrm{v}=\alpha \mathrm{t}+\beta \mathrm{t}^2$, where $\alpha$ and $\beta$ are constants. The distance travelled by the particle between 1 s and 2 s is:

Select the correct option:

$3 \alpha+7 \beta$

$\frac{3}{2} \alpha+\frac{7}{3} \beta$

$\frac{\alpha}{2}+\frac{\beta}{3}$

$\frac{3}{2} \alpha+\frac{7}{2} \beta$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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