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JEE-MAIN 2019
12-01-2019 S1
Question
The integral $\int \cos \left(\log _e x\right) d x$ is equal to (where $C$ is a constant of integration)
Select the correct option:
A
(1) $x\left[\cos \left(\log _e x\right)-\sin \left(\log _e x\right)\right]+C$ (4) $x\left[\cos \left(\log _e x\right)+\sin \left(\log _e x\right)\right]+C$
B
$\frac{x}{2}\left[\cos \left(\log _e x\right)+\sin \left(\log _e x\right)\right]+C$
C
$\frac{x}{2}\left[\sin \left(\log _e x\right)-\cos \left(\log _e x\right)\right]+C$
D
$x\left[\cos \left(\log _e x\right)+\sin \left(\log _e x\right)\right]+C$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
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