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JEE MAIN 2024
29-01-2024 SHIFT-1
Question
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is $1.5 \times 10^{-5} \mathrm{Tm}$. The magnetic moment of the dipole is $\mathrm{Am}^2$. (Given : $\frac{\mu_0}{4 \pi}=10^{-7} \mathrm{TmA}^{-1}$ )
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Question Tags
JEE Main
Physics
Medium
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