Liquid Solution | JEE Main 2025 | Molarity of Aqueous Acid

JEE MAIN 2025

28-01-2025 SHIFT-1

Question

The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is _____ $ \times {10^{ - 1}}$ M(Nearest integer)
[Given: Density of aqueous solution of (X) is $1.25\;{\rm{g}}\;{\rm{m}}{{\rm{L}}^{ - 1}}$
Molar mass of the acid is $70\;{\rm{g}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$]

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Solution

Assuming 100 gm solution contain 70 gm solute. Volume of 100 gm solution will be $\frac{{100}}{{1.25}}{\rm{ml}}$.
${\rm{ Molarity }} = \frac{{70/70}}{{100/1.25}} \times 1000 = 12.5{\rm{ or }}125 \times {10^{ - 1}}$

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JEE Main

Chemistry

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