The number of $\mathrm{sp}^2$ hybrid orbitals in a molecule of benzene is
Select the correct option:
A
24
B
18
C
12
D
6
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Each carbon atom is $\mathrm{sp}^2$ hybrid
$\therefore \quad 3 \mathrm{sp}^2$ hybrid orbitals are formed by each carbon atom
Total sp ${ }^2$ orbitals $=6 \times 3=18$
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