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JEE MAIN 2023
11-4-2023
Question
The surface tension of soap solution is $3.5 \times 10^{-2} \mathrm{Nm}^{-1}$. The amount of work done required to increase the radius of soap bubble from 10 cm to 20 cm is $\_\_\_\_$ $\times 10^{-4} \mathrm{~J}$.
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Solution
$\begin{array}{ll}\text { Sol. } & W=T .(\Delta A) \\ & W=T\left(8 \pi\left(r_2^2-r_1^2\right)\right) \\ & W=264 \times 10^{-4} \mathrm{~J}\end{array}$
Question Tags
JEE Main
Chemistry
Medium
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