The trajectory of..... | JEE Main 2023

JEE MAIN 2023

8-4-2023 S2

Question

The trajectory of projectile, projected from the ground is given by $y=x-\frac{x^2}{20}$. Where $x$ and $y$ are measured in meter. The maximum height attained by the projectile will be-

Select the correct option:

5 m

$10 \sqrt{2} \mathrm{~m}$

200 m

10 m

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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