The value of $\int_{{{{e}^{2}}}}^{{{{e}^{4}}}}{{\frac{1}{x}}}\left( {\frac{{{{e}^{{{{{\left( {{{{\left( {{{{\log }}_{e}}x} \right)}}^{2}}+1} \right)}}^{{-1}}}}}}}}{{{{e}^{{{{{\left( {{{{\left( {{{{\log }}_{e}}x} \right)}}^{2}}+1} \right)}}^{{-1}}}}}}+{{e}^{{{{{\left( {{{{\left( {6-{{{\log }}_{e}}x} \right)}}^{2}}+1} \right)}}^{{-1}}}}}}}}} \right)dx$ is