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JEE Advanced 2025 - Mathematics
28-01-2025 SHIFT-2
Question
The volume contraction of a solid copper cube of edge length 10 cm , when subjected to a hydraulic pressure of $7 \times 10^{6} \mathrm{~Pa}$, would be $\_\_\_\_$ $\mathrm{mm}^{3}$. (Given bulk modulus of copper $=1.4 \times 10^{11} \mathrm{Nm}^{-2}$ )
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Solution
$\mathrm{B}=\frac{\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}} ; \Delta \mathrm{V}=\frac{7 \times 10^{6}}{1.4 \times 10^{11}} \times\left(10 \times 10^{-2}\right)^{3} ; \Delta \mathrm{V}=50 \mathrm{~mm}^{3}$
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