The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as $\mathrm{R}_1$ has the colour code (Orange, Red, Brown). The resistors $\mathrm{R}_2$ and $\mathrm{R}_4$ are $80 \Omega$ and $40 \Omega$ respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as $\mathrm{R}_3$, would be be: