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JEE MAIN 2021
24-02-2021 S2
Question
Two solids A and B of mass 1 kg and 2 kg respectively are moving with equal linear momentum. The ratio of their kinetic energies $\left(K \mathrm{E}_{-}\right)_A:\left(K \mathrm{E}_{-}\right)_B$ will be $\frac{A}{1}$, so the value of $A$ will be $\_\_\_\_$ .
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Question Tags
JEE Main
Physics
Easy
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