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JEE MAIN 2023
31-01-2023 S1
Question
When $\mathrm{Cu}^{2+}$ ion is treated with KI , a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound $Y$ is formed. $X$ and $Y$ respectively are
Select the correct option:
A
$\mathrm{X}=\mathrm{Cu}_2 \mathrm{I}_2 \quad \mathrm{Y}=\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_5$
B
$\mathrm{X}=\mathrm{Cu}_2 \mathrm{I}_2 \quad \mathrm{Y}=\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$
C
$\mathrm{X}=\mathrm{CuI}_2 \quad \mathrm{Y}=\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_3$
D
$\mathrm{X}=\mathrm{CuI}_2 \quad \mathrm{Y}=\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Medium
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