The de Broglie wavelength... |JEE Main 2023

JEE MAIN 2023

15-04-2023 S1

Question

The de Broglie wavelength of an electron having kinetic energy $E$ is $\lambda$. If the kinetic energy of electron becomes $\frac{E}{4}$, then its de-Broglie wavelength will be :

Select the correct option:

$\frac{\lambda}{\sqrt{2}}$

$\frac{\lambda}{2}$

$2 \lambda$

$\sqrt{2} \lambda \mid$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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