Skip to content
Courses
Test Series
Books
Free Resources
Result
Contact Us
Courses
Test Series
JEE Solutions
NCERT PDF
Books
Free Resources
Gallery
Result
Blogs
Watch JEE/NEET Free Lectures
↗
Download Our App
↗
Follow Us
Login / Register
Back
Report
Report Issue
×
Wrong Answer
Typo Error
Image Issue
Not Clear
Other
JEE MAIN 2025
22-01-2025 SHIFT-1
Question
The product of all solutions of the equation $\mathrm{e}^{5\left(\log _{\mathrm{c}} x\right)^2+3}=x^8, x>0$, is :
Select the correct option:
A
${e^2}$
B
$e$
C
${e^{8/5}}$
D
${e^{6/5}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
View Solution
Solution
$\begin{aligned} & \mathrm{e}^{5(\ln \mathrm{x})^2+3}=\mathrm{x}^8 \\ & \Rightarrow \int \mathrm{ne}^{5(\ln x)^2+3}=\ln \mathrm{x}^8 \\ & \Rightarrow 5(\ln \mathrm{x})^2+3=8 \ln \mathrm{x} \\ & (\operatorname{lnx}=\mathrm{t}) \\ & \Rightarrow 5 \mathrm{t}^2-8 \mathrm{t}+3=0 \\ & \quad \mathrm{t}_1+\mathrm{t}_2=\frac{8}{5} \\ & \quad \ln \mathrm{x}_1 \mathrm{x}_2=\frac{8}{5} \\ & \mathrm{x}_1 \mathrm{x}_2=\mathrm{e}^{8 / 5}\end{aligned}$
Question Tags
JEE Main
Mathematics
Easy
Start Preparing for JEE with Competishun
YouTube
Books
App
Tests
Scan the code
Powered by
Joinchat
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation.
Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
Open Chat