Let the point $\mathrm{P}(\alpha, \beta)$ be at a unit distance from each of the two lines $\mathrm{L}_1: 3 \mathrm{x}-4 \mathrm{y}+12=0$, and $\mathrm{L}_2: 8 \mathrm{x}+6 \mathrm{y}+11=$ 0 . If P lies below $\mathrm{L}_1$ and above $\mathrm{L}_2$, then $100(\alpha+\beta)$ is equal to
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