If $(a+\sqrt{2} b \cos x)(a-\sqrt{2 b} \cos y)=a^2-b^2$, where $a >\mathrm{b}>0$, then $\frac{\mathrm{dx}}{\mathrm{dy}} \mathrm{at}\left(\frac{\pi}{4}, \frac{\pi}{4}\right)$ is :
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