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JEE MAIN 2025
04-04-2025 SHIFT-1
Question
Let $A = \left[ {\begin{array}{*{20}{c}} {\cos \theta }&0&{ - \sin \theta }\\ 0&1&0\\ {\sin \theta }&0&{\cos \theta } \end{array}} \right]$. If for some $\theta \in (0,\pi ),{A^2} = {A^T}$, then the sum of the diagonal elements of the matrix ${({\rm{A}} + {\rm{I}})^3} + {({\rm{A}} - {\rm{I}})^3} - 6\;{\rm{A}}$ is equal to __________.
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Question Tags
JEE Main
Physics
Hard
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