Among the electrolytes $\mathrm{Na}_2 \mathrm{SO}_4, \mathrm{CaCl}_2, \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3$ and $\mathrm{NH}_4 \mathrm{Cl}$, the most effective coagulating agent for $\mathrm{Sb}_2 \mathrm{~S}_3$ sol is
Select the correct option:
A
$\mathrm{Na}_2 \mathrm{SO}_4$
B
$\mathrm{CaCl}_2$
C
$\mathrm{Al}_2\left(\mathrm{SO}_4\right)_3$
D
$\mathrm{NH}_4 \mathrm{Cl}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
As $\mathrm{Sb}_2 \mathrm{~S}_3$ is a negative sol, so, $\mathrm{Al}_2\left(\mathrm{SO}_4\right)_3$ will be the most effective coagulant due to higher charge density on $\mathrm{Al}^{3+}$ in accordance with Hardy-Schulze rule.
Order of effectiveness of cations: $\mathrm{Al}^{3+}>\mathrm{Ca}^{++}>\mathrm{Na}^{+}>\mathrm{NH}_4^{+}$
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