Binomial Theorem_JEE MAIN_11-01-2019_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2019

11-01-2019 S2

Question

Let $(x+10)^{50}+(x-10)^{50} =a_0+a_1 x+a_2 x^2+\ldots+a_{50} x^{50}$, for all $x \in R$ : then $\frac{a_2}{a_0}$ is equal to :

Select the correct option:

A

12.25

B

12.75

C

12.00

D

12.50

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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