Let (x+10)^50+(x−10)^50=a₀+a₁x... | Binomial Theorem

JEE MAIN 2019

11-01-2019 S2

Question

Let $(x+10)^{50}+(x-10)^{50} =a_0+a_1 x+a_2 x^2+\ldots+a_{50} x^{50}$, for all $x \in R$ : then $\frac{a_2}{a_0}$ is equal to :

Select the correct option:

12.25

12.75

12.00

12.50

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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