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JEE-Main 2024
06.04.24_(S1)
Question
Let $\mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3, \mathrm{x}_4$ be the solution of the equation $4 x^4+8 x^3-17 x^2-12 x+9=0$ and $\left(4+x_1^2\right)\left(4+x_2^2\right)(4+ \left.x_3^2\right)\left(4+x_4^2\right)=\frac{125}{16} m$. Then the value of $m$ is $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Easy
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