The correct statements among the following are,
A. $\mathrm{Mo}(\mathrm{VI})$ and $\mathrm{W}(\mathrm{VI})$ are less stable than $\mathrm{Cr}(\mathrm{VI})$.
B. $\mathrm{Ce}^{4+}$ and $\mathrm{Tb}^{4+}$ are oxidant while $\mathrm{Eu}^{2+}$ and $\mathrm{Yb}^{2+}$ are reductant.
C. Cm and Am have seven unpaired electrons.
D. Actinoid contraction is greater from element to element than lanthanoid contraction.
Choose the correct answer from the options given below:
Select the correct option:
A
(1) A and B Only (2) C and D Only (3) B and D Only (4) A and C Only
B
(1) A and B Only (2) C and D Only (3) B and D Only (4) A and C Only
C
(1) A and B Only (2) C and D Only (3) B and D Only (4) A and C Only
D
(1) A and B Only (2) C and D Only (3) B and D Only (4) A and C Only
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
(A) $\mathrm{Mo}(\mathrm{VI})$ \& $\mathrm{W}(\mathrm{VI})$ more stable than $\mathrm{Cr}(\mathrm{VI})$
(B) In lanthanoids +3 oxidation state is more stable hance +4 ions act as oxidising agents and +2 ions act as reducing agents.
(C) $\mathrm{Cm}-[\mathrm{Rn}] 5 \mathrm{f}^7 6 \mathrm{~d}^1 7 \mathrm{~S}^2=8$ unpaired electrons
$\mathrm{Am}-[\mathrm{Rn}] 5 \mathrm{f}^7 7 \mathrm{~S}^2=7$ unpaired electrons
(D) Actinoid contraction is more than lanthanoid contraction
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