Let $\alpha, \beta \in \mathbf{R}$ be such that the system of linear equations $$
\begin{aligned}
& x+2 y+z=5 \\
& 2 x+y+\alpha z=5 \\
& 8 x+4 y+\beta z=18
\end{aligned}
$$
has no solution. Then $\frac{\beta}{\alpha}$ is equal to:
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