From the circuit given below, the capacitance between terminals $A$ and $B$ shown in the circuit is $\_\_\_\_$ $\mu \mathrm{F}$. (take $\mathrm{C}_1=\mathrm{C}_2=\mathrm{C}_3=1 \mu \mathrm{~F}$ and $\mathrm{C}_4=2 \mu \mathrm{~F}$ ) [JEE MAIN_040426_S2][CPC_C][Ea\$y]
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