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JEE MAIN
01-02-2024 S1
Question
A particle is moving in one dimension (along x axis) under the action of a variable force. It's initial position was 16" " m right of origin. The variation of its position (x) with time (t) is given as $x=-3 t^3+18 t^2+16 t$, where x is in m and t is in s. The velocity of the particle when its acceleration becomes zero is m/s.
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Question Tags
JEE Main
Physics
Medium
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