A carrier wave of amplitude 15V is modulated by a sinusoidal base band signal of amplitude 3V. The ratio of maximum amplitude to minimum amplitude in an amplitude modulated wave is :
Select the correct option:
A
2
B
$\frac{3}{2}$
C
5
D
1
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Ans. (2)
Sol. Given, $\mathrm{A}_{\mathrm{c}}=15 \mathrm{~V}$
$$
\mathrm{A}_{\mathrm{m}}=3 \mathrm{~V}
$$
Maximum amplitude of modulated wave
$$
A_{\max }=A_c+A_m=15+3=18 \mathrm{~V}
$$
Minimum amplitude of modulated wave
$$
\begin{aligned}
& A_{\min }=A_c-A_m=15-3=12 V \\
& \therefore \frac{A_c+A_m}{A_c-A_m}=\frac{18}{12}=\frac{3}{2}
\end{aligned}
$$
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