The geometry around boron|The p-Block Elements|JEEMAIN 2022

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JEE-Main 2022

25-7-2022_S-1

Question

The geometry around boron in the product ' B ' formed from the following reaction is $$ \begin{aligned} & \mathrm{BF}_3+\mathrm{NaH} \xrightarrow{450 \mathrm{~K}} \mathrm{~A}+\mathrm{NaF} \\ & \mathrm{~A}+\mathrm{NMe}_3 \rightarrow \mathrm{~B} \end{aligned} $$

Select the correct option:

A

trigonal planar

B

tetrahedral

C

pyramidal

D

square planar

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Solution

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