Report Issue

JEE-MAIN 2021
17-03-2021 S2
Question
A $2 \mu \mathrm{~F}$ capacitor $\mathrm{C}_1$ is first charged to a potential difference of 10 V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor $\mathrm{C}_2$ of $8 \mu \mathrm{~F}$. The charge in $\mathrm{C}_2$ on equilibrium condition is $\_\_\_\_$ $\mu \mathrm{C}$. (Round off to the Nearest Integer)
Question Image
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Easy
Start Preparing for JEE with Competishun