Consider the function f: R → R... | Continuity JEE Main 2021

JEE-MAIN 2021

17-03-2021 S2

Question

Consider the function $f: R \rightarrow R$ defined by $$ f(x)=\left\{\begin{array}{cl} \left(2 \sin \left(\frac{1}{x}\right)\right)|x|, & x \neq 0 \\ 0 & , x=0 \end{array} \text {. Then } f\right. \text { is: } $$

Select the correct option:

monotonic of $(-\infty, 0) \cup(0, \infty)$

not monotonic on $(-\infty, 0)$ and $(0, \infty)$

monotonic on $(0, \infty)$ only

monotonic on $(-\infty, 0)$ onl,

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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