The value of the integral... | Definite Integrals JEE main 2021

JEE MAIN 2021

20-07-2021 S1

Question

The value of the integral $\int_{-1}^1 \log _e(\sqrt{1-x}+\sqrt{1+x}) d x$ is equal to :

Select the correct option:

$\frac{1}{2} \log _e 2+\frac{\pi}{4}-\frac{3}{2}$

$2 \log _e 2+\frac{\pi}{4}-1$

$\log _e 2+\frac{\pi}{2}-1$

$2 \log _e 2+\frac{\pi}{2}-\frac{1}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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