In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position
Select the correct option:
A
$\frac{1}{2}$
B
$\frac{3}{4}$
C
$\frac{1}{3}$
D
$\frac{1}{4}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & K=\frac{1}{2} m \omega^2\left(A^2-x^2\right) \\ & =\frac{1}{2} m \omega^2\left(A^2-\frac{A^2}{4}\right) \\ & =\frac{1}{2} m \omega^2\left(\frac{3 A^2}{4}\right) \\ & K=\frac{3}{4}\left(\frac{1}{2} m \omega^2 A^2\right)\end{aligned}$
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