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JEE-MAIN 2021
27-08-2021 S2
Question
Two simple harmonic motion, are represented by the equations $y_1=10 \sin \left(3 \pi t+\frac{\pi}{3}\right)$ $$ y_2=5(\sin 3 \pi t+\sqrt{3} \cos 3 \pi t) $$ Ratio of amplitude of $y_1$ to $y_2=x: 1$. The value of $x$ is $\_\_\_\_$
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JEE Main
Physics
Easy
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