The reaction of $\mathrm{H}_3 \mathrm{~N}_3 \mathrm{~B}_3 \mathrm{Cl}_3$ (A) with $\mathrm{LiBH}_4$ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to $\mathrm{H}_3 \mathrm{~N}_3 \mathrm{~B}_3(\mathrm{Me})_3$. Compounds (B) and (C) respectively, are
