Let a function be continuous defined

JEE MAIN 2020

09-01-2020 S2

Question

Let a function $f:[0,5] \rightarrow R$ be continuous, $f(1)=3$ and $F$ be defined as : $$ F(x)=\int_1^x t^2 g(t) d t, \text { where } g(t)=\int_1^t f(u) d u $$ Then for the function F , the point $\mathrm{x}=1$ is

Select the correct option:

a point of inflection.

not a critical point.

a point of local minima.

a point of local maxima.

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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