When a particle of mass|SIMPLE HARMONIC MOTION|JEE-Main 2020

JEE MAIN 2020

06-09-2020 S2

Question

When a particle of mass $m$ is attached to a vertical spring of spring constant $k$ and released, its motion is described by $y(t)=y_0 \sin 2 \omega t$, where ' $y$ ' is measured from the lower end of unstretched spring. Then $\omega$ is

Select the correct option:

$\sqrt{\frac{2 g}{y_0}}$

$\frac{1}{2} \sqrt{\frac{g}{y_0}}$

$\sqrt{\frac{g}{2 y_0}}$

$\sqrt{\frac{\mathrm{g}}{\mathrm{y}_0}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Hard

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