Definite Integration_JEE-Main 2019_09-01-2019_S2 - Competishun

JEE MAIN 2019

09-01-19 S2

Question

$ \int_0^{\pi / 3} \frac{\tan \theta}{\sqrt{2 \mathrm{ksec} \theta}} \mathrm{~d} \theta=1-\frac{1}{\sqrt{2}},(\mathrm{k}>0) $ then the value of $k$ is

Select the correct option:

$\frac{1}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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