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JEE MAIN 2026
21-01-2026 S2
Question
Let one end of a focal chord of the parabola $y^2=16 x$ be $(16,16)$. If $\mathrm{P}(\alpha, \beta)$ divides this focal chord internally in the ratio $5: 2$, then the minimum value of $\alpha+\beta$ is equal to :
Select the correct option:
A
22
B
7
C
5
D
16
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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