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Jee Main 2024
31-01-2024 (S2)
Question
The temperature $\mathrm{T}(\mathrm{t})$ of a body at time $\mathrm{t}=0$ is $160^{\circ} \mathrm{F}$ and it decreases continuously as per the differential equation ${ }^{\mathrm{dT}} \_=-K(T-80)$, where $K$ is positive constant. If $T(15)=120^{\circ} F$, then $T(45)$ is equal to
Select the correct option:
A
$85^{\circ} \mathrm{F}$
B
$95^{\circ} \mathrm{F}$
C
$90^{\circ} \mathrm{F}$
D
$80^{\circ} \mathrm{F}$
✓ Correct! Well done.
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Solution
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JEE Main
Mathematics
Medium
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