The equilibrium constant for the | Chemistry | JEE Main 2024

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JEE Main 2024

04-04-2024 S2

Question

The equilibrium constant for the reaction
$ \mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) $
is $K_C=4.9 \times 10^{-2}$. The value of $K_C$ for the reaction given below is $2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ is

Select the correct option:

A

4.9

B

41.6

C

49

D

416

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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