Let ABC an isosceles | Solution of Triangles | JEE main 2024

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JEE MAIN 2024

1-2-2024 S2

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Let ABC be an isosceles triangle in which A is at $(-1,0), \angle A=\frac{2 \pi}{3}, A B=A C$ and $B$ is on the positive x -axis. If $\mathrm{BC}=4 \sqrt{3}$ and the line BC intersects the line $y=x+3$ at $(\alpha, \beta)$, then $\frac{\beta^4}{\alpha^2}$ is:

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