Parabola | JEE Main 2024 Solution | Shortest Distance

JEE MAIN 2024

27-01-2024 SHIFT-1

Question

If the shortest distance of the parabola $y^2=4 x$ from the centre of the circle $x^2+y^2-4 x-16 y+64=0$ is d , then $\mathrm{d}^2$ is equal to :

Select the correct option:

A

16

B

24

C

20

D

36

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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