Let the foci of a hyperbola | HYPERBOLA | JEE Main 2024

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JEE Main 2024

09-04-2024 S2

Question

Let the foci of a hyperbola H coincide with the foci of the ellipse $E: \frac{(x-1)^2}{100}+\frac{(y-1)^2}{75}=1$ and the eccentricity of the hyperbola H be the reciprocal of the eccentricity of the ellipse E . If the length of the transverse axis of H is $\alpha$ and the length of its conjugate axis is $\beta$, then $3 \alpha^2+2 \beta^2$ is equal to :

Select the correct option:

A

242

B

225

C

237

D

205

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

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