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JEE Advance 2020
paper 1
Multiple correct answers - Select all that apply
Question
A particle of mass m moves in circular orbits with potential energy $\mathrm{V}(\mathrm{r})=F r$, where F is a positive constant and $r$ is its distance from the origin. Its energies are calculated using the Bohr model. If the radius of the particle's orbit is denoted by R and its speed and energy are denoted by v and E , respectively, then for the $\mathrm{n}^{\text {th }}$ orbit (here h is the Planck's constant)-
Select ALL correct options:
A
$\mathrm{R} \propto \mathrm{n}^{1 / 3}$ and $\mathrm{v} \propto \mathrm{n}^{2 / 3}$
B
$\mathrm{R} \propto \mathrm{n}^{2 / 3}$ and $\mathrm{v} \propto \mathrm{n}^{1 / 3}$
C
$E=\frac{3}{2}\left(\frac{n^2 h^2 F^2}{4 \pi^2 m}\right)^{1 / 3}$
D
$E=2\left(\frac{n^2 h^2 F^2}{4 \pi^2 m}\right)^{1 / 3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
Sol. $\mathrm{U}=\mathrm{Fr}$ [Using $U=$ Potential energy and $v=$ velocity, to avoid confusion between their symbols] ⇒ Force $=\frac{-\mathrm{dU}}{\mathrm{dr}}=-\mathrm{F}$ ⇒ Magnitude of force $=$ Constant $=$ F $$ \Rightarrow F=\frac{m v^2}{R} $$ $$ \Rightarrow \mathrm{mvR}=\frac{\mathrm{nh}}{2 \pi} $$ $$ \begin{aligned} & \Rightarrow \mathrm{F}=\frac{\mathrm{m}}{\mathrm{R}} \times \frac{\mathrm{n}^2 \mathrm{~h}^2}{4 \pi^2} \times \frac{1}{\mathrm{~m}^2 \mathrm{R}^2} \\ & \Rightarrow \mathrm{R}=\left(\frac{\mathrm{n}^2 \mathrm{~h}^2}{4 \pi^2 \mathrm{mF}}\right)^{1 / 3} \\ & \Rightarrow \mathrm{v}=\frac{\mathrm{nh}}{2 \pi \mathrm{mR}} \end{aligned} $$
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