A straight wire AB of and length suspended by a pair

JEE MAIN 2023

13-04-2023 S2

Question

A straight wire AB of mass 40 g and length 50 cm is suspended by a pair of flexible leads in uniform magnetic field of magnitude 0.40 T as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is ________A. (Take $\mathrm{g}=10 \mathrm{~ms}^{-2}$ ).

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Solution

For equilibrium $$ \begin{aligned} & M g=I \ell B \\ & I=\frac{m g}{\ell B}=\frac{40 \times 10^{-3} \times 10}{50 \times 10^{-2} \times 0.4}=2 \mathrm{~A} \end{aligned} $$

Question Tags

JEE Main

Physics

Easy

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