A tuning fork of frequency 480 Hz |SOUND WAVE|JEE-Main-2019

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JEE MAIN 2019

12-04-2019 S2

Question

A tuning fork of frequency 480 Hz is used in an experiment for measuring speed of sound (v) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, $\mathrm{I}_1=30 \mathrm{~cm}$ and $\mathrm{I}_2=$ 70 cm . Then, v is equal to

Select the correct option:

A

$332 \mathrm{~ms}^{-1}$

B

$384 \mathrm{~ms}^{-1}$

C

$379 \mathrm{~ms}^{-1}$

D

$338 \mathrm{~ms}^{-1}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{array}{ll}\mathrm{I}_1= & 30 \mathrm{~cm}, \mathrm{I}_2=70 \mathrm{~cm} \\ \therefore & \frac{\lambda}{2}=\left(\mathrm{I}_2-\mathrm{I}_1\right)=40 \mathrm{~cm} \\ \Rightarrow & \lambda=80 \mathrm{~cm} \\ \therefore & \mathrm{U}=v \lambda=480 \times(0.8) \mathrm{m} / \mathrm{s} \\ & =384 \mathrm{~m} / \mathrm{s}\end{array}$

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