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JEE MAIN 2025
02-04-2025 SHIFT-2
Question
A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by force of 10 N as shown in figure. The established torque produces an angular acceleration of $2 \mathrm{rad} / \mathrm{s}^{2}$. Moment of intertia of the wheel is $\_\_\_\_$ $\mathrm{kgm}^{2}$. (Acceleration due to gravity $=10 \mathrm{~m} / \mathrm{s}^{2}$ )
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Question Tags
JEE Main
Physics
Easy
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