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JEE MAIN 2024
04-08-2024 S1
Question
An electron with kinetic energy 5eV enters a region of uniform magnetic field of 3μT perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that electron moves along the same path, is______ $\mathrm{NC}^{-1}$. (Given, mass of electron$=9 \times 10^{-31} \mathrm{~kg}$, electric charge $=1.6 \times 10^{-19} \mathrm{C}$ C )
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Question Tags
JEE Main
Physics
Medium
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