Given at 298 K.... | Electrochemistry | Jee Main 2026

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08-04-26_S2

Question

Given at 298 K :

$$
\begin{aligned}
& \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{!}=\mathrm{X} \text { Volt } \\
& \mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}}^{!}=\mathrm{Y} \text { Volt }
\end{aligned}
$$


The $\mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^{!}$in Volt at 298 K is given by :

Select the correct option:

A

$2 X-3 Y$

B

$3 Y-2 X$

C

$3 Y+2 X$

D

$Y+X$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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