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JEE MAIN 2023
12-04-2023 S1
Question
If the point $\left(\alpha, \frac{7 \sqrt{3}}{3}\right)$ lies on the curve traced by the mid-points of the line segments of the lines $x \cos \theta +\mathrm{y} \sin \theta=7, \theta \in\left(0, \frac{\pi}{2}\right)$ between the co-ordinates axes, then $\alpha$ is equal to -
Select the correct option:
A
7
B
-7
C
$-7 \sqrt{3}$
D
$7 \sqrt{3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
If the point $\left(\alpha, \frac{7 \sqrt{3}}{3}\right)$ lies on the curve traced by the mid-points of the line segments of the lines $x \cos \theta +\mathrm{y} \sin \theta=7, \theta \in\left(0, \frac{\pi}{2}\right)$ between the co-ordinates axes, then $\alpha$ is equal to -
Solution Image
Question Tags
JEE Main
Mathematics
Medium
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