Let $y=y(x)$ be the solution curve of the differential equation $(1+\sin x) \frac{\mathrm{d} y}{\mathrm{~d} x}+(y+1) \cos x=0, y(0)=0$. If the curve $y=y(x)$ passes through the point $\left(\alpha, \frac{-1}{2}\right)$, then a value of $\alpha$ is :
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
